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I don't get it but here some help with logs:

log x base y = log x / log y (when log x is default base 10 in calculators) and

log (x*y) = log x + log y

log (x/y) = log x - log y

the bases is default 10

hope it's helped

Posted on Jul 06, 2009

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Posted on Jan 02, 2017

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Residents of Canada:

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Jul 08, 2014 | DeLonghi EC155 Espresso Machine

Authentication stage error: Server reported error:No more upgrade logs. Please contact your reseller.

Mar 22, 2013 | Cell Phones

You calculate the pH with the relation

pH=-log(c) where c is the value of concentration in mol/L.

ex: c[H+]= 3.57x10^(-6)

pH: (-) [LOG] 3.57 [2nd][EE] [(-)] 6 [ ) ]

Here you have 2 change sign key press [(-)]

If you have the pH, and want to calculate the concentration that yields that value of the pH you proceed as follows

c= 10^(-pH)

Ex pH=8.23

c: [2nd][LOG] [(-) 8.23 [)]

General shortcut.

If concentration is of the form c[H+]= 1*10^(-a) where a is an integer between 0 and 14, the pH is equal to the positive value of exponent.

Ex:c[H+]=1x10^(-5) Mol/L then the pH is just the positive value of the exponent, ie 5 because pH=-log(1.x10^-5) =- log1 -log(10^-5)=0 -(-5)=5

Above I use the rule log(axb)=log(a)+log(b) , the rule log(a^b) = b*log(a)and the facts that log(1)=0 and log(10)=1, the last being true if log stands for log in base 10.

pH=-log(c) where c is the value of concentration in mol/L.

ex: c[H+]= 3.57x10^(-6)

pH: (-) [LOG] 3.57 [2nd][EE] [(-)] 6 [ ) ]

Here you have 2 change sign key press [(-)]

If you have the pH, and want to calculate the concentration that yields that value of the pH you proceed as follows

c= 10^(-pH)

Ex pH=8.23

c: [2nd][LOG] [(-) 8.23 [)]

General shortcut.

If concentration is of the form c[H+]= 1*10^(-a) where a is an integer between 0 and 14, the pH is equal to the positive value of exponent.

Ex:c[H+]=1x10^(-5) Mol/L then the pH is just the positive value of the exponent, ie 5 because pH=-log(1.x10^-5) =- log1 -log(10^-5)=0 -(-5)=5

Above I use the rule log(axb)=log(a)+log(b) , the rule log(a^b) = b*log(a)and the facts that log(1)=0 and log(10)=1, the last being true if log stands for log in base 10.

May 17, 2011 | Texas Instruments TI-30XA Calculator

Sorry the answer comes too late for your final exam. If you took the time to really understand what the inverse of a log function is, you would have saved yourself the anxiety before the test.

Anyway, the inverse of the logarithm in base 10 IS the power function with base 10.

y=log(x) <=> x=10^(y).

Some calculator manufacturers use the marking ^-1 to represent an inverse function. But recently one sees new calculators with the new notation.

By the way, the inverse of the natural log function (LN) is the exponential function (e^(x))

Anyway, the inverse of the logarithm in base 10 IS the power function with base 10.

y=log(x) <=> x=10^(y).

Some calculator manufacturers use the marking ^-1 to represent an inverse function. But recently one sees new calculators with the new notation.

By the way, the inverse of the natural log function (LN) is the exponential function (e^(x))

May 02, 2011 | Casio fx-300ES Calculator

Pressing 2 0 0 LN = will give you the natural logarithm of 200. If you need the common (base 10) logarithm, divide the result by the log of 10.

( 2 0 0 LN ) / ( 1 0 LN ) =

will give you the common log of 200.

( 2 0 0 LN ) / ( 1 0 LN ) =

will give you the common log of 200.

Jan 05, 2011 | Texas Instruments BA-II Plus Calculator

Assuming you want the common antilog of 11/20:

2nd 10^x 1 1 / 2 0 ENTER

10^x is on the LOG key, to the left of the 7 key.

2nd 10^x 1 1 / 2 0 ENTER

10^x is on the LOG key, to the left of the 7 key.

Nov 15, 2010 | Texas Instruments TI-83 Plus Calculator

1 EE 14 LOG / 2 +<>- =

Jun 25, 2010 | Texas Instruments TI-30XA Calculator

Hello

When you talk about the natural logarithms [LN], the inverse of the log is the exponential

ln (exp(x))=exp(ln(x)) =x

but with othe logarithms, thinhs are different

Let us take

**y=10^(x)**

then with log standing as usual for log in base 10 take the log of both members in the above equality

log(y) =log{10^(x)) = x* log(10) : this is a property of the log function.

However, log(10) =1 This is also a property of the log

Gathering results, we end up with the new equality

log(y)=x or x=log(y)

Without entering into extraneous details that mathematicians adore, we can state that there is an equivalenve between y=10^(x) and x=log(y)

**y=10^(x) <-->x=log(y)** where <--> means implication in both directions.

Here is a screen capture from another calculator to convinve you. Your calculator cannot do that.

Hope it helps.

When you talk about the natural logarithms [LN], the inverse of the log is the exponential

ln (exp(x))=exp(ln(x)) =x

but with othe logarithms, thinhs are different

Let us take

then with log standing as usual for log in base 10 take the log of both members in the above equality

log(y) =log{10^(x)) = x* log(10) : this is a property of the log function.

However, log(10) =1 This is also a property of the log

Gathering results, we end up with the new equality

log(y)=x or x=log(y)

Without entering into extraneous details that mathematicians adore, we can state that there is an equivalenve between y=10^(x) and x=log(y)

Here is a screen capture from another calculator to convinve you. Your calculator cannot do that.

Hope it helps.

Oct 06, 2009 | Texas Instruments TI-30 XIIS Calculator

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4. Accept the license agreement by clicking the "I Accept" button.

5.Click on the "Do a system scan and save a log file" button. It will scan and then ask you to save the log.

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8. Paste the log in your next reply.

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Please download SmitFraudFix from this link http://siri.urz.free.fr/Fix/Smitfra... Then extract the contents to your desktop.

Open the "SmitfraudFix" folder and double-click "smitfraudfix.cmd"

Select option #1 - Search by typing 1 and press "Enter"; a text file will appear, which lists infected files (if present).

Please copy/paste the content of that report into your next reply.

Note: process.exe is detected by some antivirus programs (AntiVir, Dr.Web,Kaspersky) as a "RiskTool"; it is not a virus, but a program used tostop system processes. Antivirus programs cannot distinguish between"good" and "malicious" use of such programs, therefore they may alertthe user.

Jan 27, 2009 | Computers & Internet

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