I put in an equation in the Y= then hit the graph key, the x and y axis show up then dots start crossing the screen, then it says Err: invalid dim

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Having gone over a month without a response, I assume turning off the stat plot features did the trick.

Posted on May 19, 2010

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Posted on Jan 02, 2017

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Choose one of the inequality type graphs

by pressing F3 Type.

Press F6 for the arrow on the right, you will get the other types

For example press F1 to select the Y greater than type graph.

Notice that on the top line Graph Func: Y>. From now on all the graphs you will draw will be Y> some function in X.

Start entering the function. As you start the screen will show Y1>

Enter the function for example sin(X^2). Use the X, theta, T to input the X variable.

Press the EXE key to complete the function line. The screen will look like on the following screen grab

Press the F6 key Draw to get your graph and the shaded region, as on the following picture:

by pressing F3 Type.

Press F6 for the arrow on the right, you will get the other types

For example press F1 to select the Y greater than type graph.

Notice that on the top line Graph Func: Y>. From now on all the graphs you will draw will be Y> some function in X.

Start entering the function. As you start the screen will show Y1>

Enter the function for example sin(X^2). Use the X, theta, T to input the X variable.

Press the EXE key to complete the function line. The screen will look like on the following screen grab

Press the F6 key Draw to get your graph and the shaded region, as on the following picture:

Jun 22, 2017 | Casio FX-9750GII Graphing Calculator

That is an equation describing a straight line. The "slope-intercept" form of a line is

y = mx + b

where m is the slope (change in y-value / change in x-value)

and b is the y-intercept (the point where the line crosses the y-axis when x=0)

Positive slope means the line is rising and negative slope means it's falling.

You can rewrite the original equation 2x - 4y -9 = 0 in slope-intercept form:

y = (1/2)x - (9/4)

So you know the slope is positive 1/2 (line rises 1 y-unit for each 2 x-unit change) and crosses the y-axis at -9/4. With this information you can graph the line.

y = mx + b

where m is the slope (change in y-value / change in x-value)

and b is the y-intercept (the point where the line crosses the y-axis when x=0)

Positive slope means the line is rising and negative slope means it's falling.

You can rewrite the original equation 2x - 4y -9 = 0 in slope-intercept form:

y = (1/2)x - (9/4)

So you know the slope is positive 1/2 (line rises 1 y-unit for each 2 x-unit change) and crosses the y-axis at -9/4. With this information you can graph the line.

Jul 12, 2011 | Sewing Machines

You need to fix your graph so that it shows the correct y-axis and x-axis.

It works best if you press the zoom button and then scroll to find the ZoomFit option.

Then the graph should show up.

It works best if you press the zoom button and then scroll to find the ZoomFit option.

Then the graph should show up.

Jun 15, 2011 | Texas Instruments TI-84 Plus Calculator

I am not quite sure how the major axis of your hyperbola is directed and i do not know if the lengths you give are measures of the major and minor axes or the measures of the semi-major and semi-minor axes. So I am giving you the equations and the graphs so that you can decide for yourself what is appropriate for your problem.

Major axis parallel to the X-axis

Equation and graph

Center is at x=1 and y=-2, semi-major axis length is a=6, and semi-minor axis length is b=12

Major axis is parallel to the y-axis

Equation

Center is at x=1 and y=-2, semi-major axis length is a=12, and semi-minor axis length is b=6.

I trust you can customize the equations to fit your need.

Major axis parallel to the X-axis

Equation and graph

Center is at x=1 and y=-2, semi-major axis length is a=6, and semi-minor axis length is b=12

Major axis is parallel to the y-axis

Equation

Center is at x=1 and y=-2, semi-major axis length is a=12, and semi-minor axis length is b=6.

I trust you can customize the equations to fit your need.

Mar 24, 2011 | Office Equipment & Supplies

Hello,

It seems that wires got crossed. I suggest you reset all RAM by the follwing steps

[2nd][MEM][7:Reset][1:All Ram][2:Reset][ENTER]

Ram cleared will be displayed on screen. [CLEAR] to go to the home screen.

If that does not solve your problem, reinstall the OS. Post a question on how to install OS, if you want, or read some of the posts on TI83/84/89 about same subject.

If nothing works, I am afraid you will have to repair the calculator.

Hope it helps.

It seems that wires got crossed. I suggest you reset all RAM by the follwing steps

[2nd][MEM][7:Reset][1:All Ram][2:Reset][ENTER]

Ram cleared will be displayed on screen. [CLEAR] to go to the home screen.

If that does not solve your problem, reinstall the OS. Post a question on how to install OS, if you want, or read some of the posts on TI83/84/89 about same subject.

If nothing works, I am afraid you will have to repair the calculator.

Hope it helps.

Sep 05, 2009 | Texas Instruments TI-84 Plus Silver...

When you get the sign change error it is either that you have mixed up the left bound and the right bound or that you are marking the left and the right bound both above the x-axis or both below the x-axis. That's why you get the sign change error. Your range values must have different signs.

Aug 19, 2009 | Texas Instruments TI-84 Plus Silver...

dont you have to chose if its quadratic or not? I'mnot 100% sure if thats right my calculator isn't working so i cant check if thats what your doing wrong ir if thats for something else

Jun 15, 2009 | Texas Instruments TI-83 Plus Calculator

did you make sure the domain, range, and scale settings are correct?

Oct 29, 2008 | Texas Instruments TI-84 Plus Calculator

try a simple equation like x^2-1 which should come out with x = 1,-1

no sign change would indicate that the graph of the curve never crosses the x axis, if you graphed the above equation and calculated the zeros, it would come out with -1, 1 which it should, but if you put in x^2+1, the graph would never cross and therefore have no sign change from pos to neg or vice versa, the left-rt are the left and right bounds or the lower and upper bounds which was corrected in later calculators, Please let me know the outcome of graphing both of the above equations and then putting them in the solver. you could also use the quadratic equation to prove the answers if you liked, hope this helps

no sign change would indicate that the graph of the curve never crosses the x axis, if you graphed the above equation and calculated the zeros, it would come out with -1, 1 which it should, but if you put in x^2+1, the graph would never cross and therefore have no sign change from pos to neg or vice versa, the left-rt are the left and right bounds or the lower and upper bounds which was corrected in later calculators, Please let me know the outcome of graphing both of the above equations and then putting them in the solver. you could also use the quadratic equation to prove the answers if you liked, hope this helps

Mar 13, 2008 | Texas Instruments TI-83 Plus Calculator

If you are using the TI 89 titanium
Go to your graph
press f1
go do to last option (format)
you can turn on your x and y axes there

Oct 31, 2007 | Texas Instruments TI-89 Calculator

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Usually answered in minutes!

You're probably trying to graph a function that does not involve stat plot features. You can correct this by turning off the stat plot features. Press "2ND" "STAT PLOT" and then select 4:PlotsOff.

Does that do any good?

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