Question about Texas Instruments TI-30XA Calculator

Ad

To calculate the common (base 10) log of 9.01, press 9 . 0 1 LOG =

To calculate the natural (base 3) log of 9.01, press 9 . 0 1 LN =

Both the LOG and LN keys are on the top row of the keyboard.

Posted on May 09, 2011

Ad

Hi there,

Save hours of searching online or wasting money on unnecessary repairs by talking to a 6YA Expert who can help you resolve this issue over the phone in a minute or two.

Best thing about this new service is that you are never placed on hold and get to talk to real repairmen in the US.

Here's a link to this great service

Good luck!

Posted on Jan 02, 2017

Ad

The TI-30XA calculates logarithms to base e and base 10. You can calculate the log of x to any base b by calculating the logarithm of x and dividing it by the logarithm of b: log(x)/log(b) or ln(x)/ln(b).

Nov 29, 2013 | Texas Instruments TI-30XA Calculator

To take the log of a number, enter the number then press the LOG button, then the =. To take the log of a negative number, enter the negative number using the +/- key just to the right of the decimal point. To calculate the negative of a log, calculate the log and then negate it using +/-. To calculate the antilog (inverse logarithm), press 2nd then LOG.

Bear in mind that LOG is the common (base-10) logarithm. For the natural (base-e) logarithm, use the LN key to its right.

Bear in mind that LOG is the common (base-10) logarithm. For the natural (base-e) logarithm, use the LN key to its right.

Nov 07, 2011 | Texas Instruments TI-30XA Calculator

The inverse of the common log function is the power function with base 10 (10^). It shares the same physical key as the log. You acees the function by pressing [2nd] [log]

Sep 09, 2011 | Texas Instruments TI-30XA Calculator

7 LOG / ( 6 * 7 LOG - 2 LOG ) =

Mar 30, 2011 | Texas Instruments TI-30XA Calculator

Do you mean the antilog? For the common antilog, use the shifted function of the LOG key (marked 10^x). For the natural antilog, use the shifted function of the LN key (marked e^x).

For example, to calculate the common antilog of 0.5, press . 5 SHIFT [10^x] = and get about 3.16. To calculate the natural antilog of 0.5, press . 5 SHIFT [e^x] = and get about 1.65.

For example, to calculate the common antilog of 0.5, press . 5 SHIFT [10^x] = and get about 3.16. To calculate the natural antilog of 0.5, press . 5 SHIFT [e^x] = and get about 1.65.

Mar 29, 2011 | Texas Instruments TI-30XA Calculator

Here is the link to the calculator manual. It will show you how to do square root calculations, percentages, other roots, and logs. As to ratios and proportions you will have to read your mathematics textbook.

Aug 26, 2010 | Texas Instruments TI-30XA Calculator

Use the relation log5(x) = log(x) / log(5) = ln(x) / ln(5)

LOG ( 1 / 625 ) / LOG 5 =

or

LN ( 1 / 625 ) / LN 5 =

LOG ( 1 / 625 ) / LOG 5 =

or

LN ( 1 / 625 ) / LN 5 =

Mar 11, 2010 | Texas Instruments TI-30XA Calculator

Hi,

Ex: calculate -log(15.32)

Here is a picture of the change sign

Hope it helps

Ex: calculate -log(15.32)

- Calculate the log 15.32 [LOG] [=] result 1.185258765
- Then press the change sign key (-) result -1.185258765

Here is a picture of the change sign

Hope it helps

Dec 13, 2009 | Texas Instruments TI-30XA Calculator

I noticed that this calculator doesn't have a natural logarithm function as well. You can can always use the fact that

ln x = (log x) /log e or since log e is approximately .43429482

ln x = (log x)/.43429482. The greatest solution and it might be worth the 15 bucks or so to get a calculator with e^x and the natural logarithm function.

ln x = (log x) /log e or since log e is approximately .43429482

ln x = (log x)/.43429482. The greatest solution and it might be worth the 15 bucks or so to get a calculator with e^x and the natural logarithm function.

Feb 20, 2009 | Texas Instruments TI-30XA Calculator

Use the inverse log key sequences "2nd LN" or "2nd LOG" depending on whether you are using natural logs or logs to base 10

Dec 10, 2007 | Texas Instruments TI-30XA Calculator

307 people viewed this question

Usually answered in minutes!

×