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volume of 10" sphere is 1000 ties that of a 1" sphere (volume scales as the cube of linear dimension). The close packed fill-factor for spheres is 0.74 (see eg http://en.wikipedia.org/wiki/Close-packing_of_spheres). Thus you will get LESS THAN 740 1" spheres into a 10" sphere (quick calculation neglecting edge effects, which is why 740 is only a bound, not the actual number)
Yes, it si possible, but as a teacher I am wary of teaching anybody how to cheat. No reflexion on you, If your teacher wanted to show you how to store formulas s/he would have done so. Awfully sorry. However, nobody nor nothing prevents you from reading the manual and learning how you do it. That is a skill worth having.
logistics- for log base 10, just divide the number by 10.
ln- divide the # by the number e (roughly 2.72)
sine, cosine, and tangent- there should be a "SIN", "COS", and "TAN" button, if not the ratio for each, respectivly is opposite/hypotnenuse, adjacent/hypoteneuse, and opposite/adjacent. (The opp/adj being side opp or adj of angle you are doing)