Question about Texas Instruments TI-84 Plus Calculator

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Graph y1 = 2x +1 if -1< x< 0

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Graph 2X PLUS 1 for X in open interval ]-1,0[

It should be entered as follows
(2X plus 1) (X larger than negative 1) (X less than zero)

In [Y=] editor and on line Y1= type your right hand side between parentheses (2X Plus 1). I use the Plus instead of the usual sign because the parser of the web site removes the sign.
[( ]2 [X,T,theta,n] [Plus] 1 [)] [(] [X,T,theta,n] [2nd][MATH] [3: larger than] [(-)] 1 [)] [(] [X,T,Theta,n] [2nd][MATH][5: less than] 0 [)]
Here are some screen captures to help you
graph y1 = 2x +1 if -1< x< 0 - ecfa24f.jpgfa02graph y1 = 2x +1 if -1< x< 0 - d83c851.jpgass=
d83c851.jpg

Posted on Oct 30, 2010

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Every time I try to graph on TI 84 it says ERR: INVALID DIM 1:QUIT I have enterered something simple y= x+2 and window is set for -10&lt;x&lt;10 and -10&lt;y&lt;10 the curser in y=...


Go to http://education.ti.com/downloads/guidebooks/graphing/84p/TI84Plus_guidebook_EN.pdf to download the manual. On page 401, you will find the following:
INVALID DIM • The ERR:INVALID DIM error message may occur if you are trying to graph a function that does not involve the stat plot features. The error can be corrected by turning off the stat plots. To turn the stat plots off, press y , and then select 4:PlotsOff. • You specified a list dimension as something other than an integer between 1 and 999. • You specified a matrix dimension as something other than an integer between 1 and 99. • You attempted to invert a matrix that is not square.

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Fibonacci formula won't graph, but will show table


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1 Answer

Hi , I haVE TI84 SILVER EDITION AND i LOST THE MANUAL ON HOW TO OPERATE IT iM TRYING TO DO GRAPH AND i CAN'T CAN YOU HELP ME I


Here is the link to the manual.
Here is a short tutorial to get you started.
First thing to do before any new type of graphing problem
1. Turn StatPlots OFF : press [2nd][STATPLOT][4:PlotsOff] [ENTER]

Second thing: Clear the statistical lists
2. Press [2nd][0][PGRM] DownArrow to point to ClrAllLists.
3.Press [ENTER][ENTER]

Third thing : Configure the graph type to be FUNCTION graph
4. Press [MODE]. If FUNC (on fourth line) is highlighted. Press [Y=] and start entering the functions.
5. If FUNC is not highlighted, use Down arrow till 4th line, highlight FUNC and press [ENTER]. Press Press [Y=] and start entering the functions.

Fourth thing: Enter function and select them for graphing
1. As you start entering the function Y1=, notice that the = sign becomes highlighted. Press [ENTER] when Y1 is typed in. Make sure the = sign for Y1 remains highlighted as cursor moves to Y2=.
2. Keep entering the functions and verifying that their = signs remain highlighted as cursor moves to another equation.
3. When finished press [ENTER]
4. Look at the graph style for each function: it is a bit of line to the left of each Y. Here is a picture of all the 7 styles.

5d53e23.jpg

To set a graph style, highlight the style to the left of the Y, and press [ENTER]. Each time you press [ENTER] you see a new style, in the order shown on picture.
Avoid the style of Y6, it is bubble, and as such will burst and disappear once graph is finished. Avoid also the triangular ones (for Y3 and Y4) they will shade areas of the graph, and may hide other functions.

Fifth thing: Graph Functions.
1. You can press [GRAPH] to see your graphs.
2. If one curve is missing (and you have not set its style to be rhe bubble), it may be due to the Window dimensions.

Sixth Thing: Set Window dimensions and Zoom.
1. Press [ZOOM][6:ZStandard] to use standard window dimensions.
2. If curve still missing, Press [ZOOM][3:Zoom Out] to zoom out so that you may be able to see a bigger range for the functions.
3. If necessary press [WINDOW] and set the Xmin, Xmax, Ymin,Ymax to values of your own.

d44f2dd.jpg

Dimensions must obey the conditions: Xmin < Xmax, and Ymin < Ymax.

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How to be solve banker algorithm?example


I m providing you this from my college notes

Banker's Algorithm


* multiple instances of resource types IMPLIES cannot use resource-allocation graph

* banks do not allocate cash unless they can satisfy customer needs when a new process enters the system

* declare in advance maximum need for each resource type

* cannot exceed the total resources of that type

* later, processes make actual request for some resources

* if the the allocation leaves system in safe state grant the resources

* otherwise, suspend process until other processes release enough resources



Banker: Data Structures define MAXN 10 /* maximum number of processes */
#define MAXM 10 /* maximum number of resource types */
int Available[MAXM]; /* Available[j] = current # of unused resource j */
int Max[MAXN][MAXM]; /* Max[i][j] = max demand of i for resource j */
int Allocation[MAXN][MAXM]; /* Allocation[i][j] = i's current allocation of j*/
int Need[MAXN][MAXM]; /* Need[i][j] = i's potential for more j */
/* Need[i][j] = Max[i][j] - Allocation[i][j] */

Notation:

X <= Y iff X[i] <= Y[i] for all i

(0,3,2,1) is less than (1,7,3,2)

(1,7,3,2) is NOT less than (0,8,2,1)

Each row of Allocation and Need are vectors: Allocation_i and Need_i



Banker: Example

Initially:

Available
A B C
10 5 7

Later Snapshot:

Max - Allocation = Need Available
A B C A B C A B C A B C
P0 7 5 3 0 1 0 7 4 3 3 3 2
P1 3 2 2 2 0 0 1 2 2
P2 9 0 2 3 0 2 6 0 0
P3 2 2 2 2 1 1 0 1 1
P4 4 3 3 0 0 2 4 3 1



Banker: Safety Algorithm

* consider some sequence of processes

* if the first process has Need less than Available

* it can run until done

* then release all of its allocated resources

* allocation is increased for next process

* if the second process has Need less than Available

* ...

* then all of the processes will be able to run eventually

* IMPLIES system is in a safe state



Banker: Safety Algorithm

STEP 1: initialize
Work := Available;
for i = 1,2,...,n
Finish[i] = false
STEP 2: find i such that both
a. Finish[i] is false
b. Need_i <= Work
if no such i, goto STEP 4
STEP 3:
Work := Work + Allocation_i
Finish[i] = true
goto STEP 2
STEP 4:
if Finish[i] = true for all i, system is in safe state



Banker: Safety Example

Using the previous example, P1,P3,P4,P2,P0 satisfies criteria.

Max - Allocation = Need <= Work Available
A B C A B C A B C A B C
P1 3 2 2 2 0 0 1 2 2 3 3 2 3 3 2
P3 2 2 2 2 1 1 0 1 1 5 3 2
P4 4 3 3 0 0 2 4 3 1 7 4 3
P2 9 0 2 3 0 2 6 0 0 7 4 5
P0 7 5 3 0 1 0 7 4 3 10 4 7
10 5 7<<< initial system



Banker: Resource-Request Algorithm

STEP 0: P_i makes Request_i for resources, say (1,0,2)
STEP 1: if Request_i <= Need_i
goto STEP 2
else ERROR
STEP 2: if Request_i <= Available
goto STEP 3
else suspend P_i
STEP 3: pretend to allocate requested resources
Available := Available - Request_i
Allocation_i := Allocation_i + Request_i;
Need_i := Need_i - Request_i
STEP 4: if pretend state is SAFE
then do a real allocation and P_i proceeds
else
restore the original state and suspend P_i



Banker: Resource-Request Algorithm [129]

Say P1 requests (1,0,2)

Compare to Need_1: (1,0,2) <= (1,2,2)

Compare to Available: (1,0,2) <= (3 3 2)

Pretend to allocate resources:

Max - Allocation = Need Available
A B C A B C A B C A B C
P0 7 5 3 0 1 0 7 4 3 2 3 0<<<
P1 3 2 2 3 0 2<<< 0 2 0<<<
P2 9 0 2 3 0 2 6 0 0
P3 2 2 2 2 1 1 0 1 1
P4 4 3 3 0 0 2 4 3 1

Is this safe? Yes: P1, P3, P4, P0, P2

Can P4 get (3,3,0)? No, (3,3,0) > (2,3,0) Available

Can P0 get (0,2,0)? (0,2,0) < (2,3,0) Available

Pretend: Available goes to (2,1,0)

Thanks And Regards

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