Questions & Answers for: log 2

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Question about FX-260 Calculator

1 Answer

log^2 24 - log^2 3 = log^5 x Here something that would help you: log x base y = log x / log y log (x*y) = log x + log y log (x/y) = log x - log y so log 24 base 2 it's log 24 / log 2 etc. and if i get

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...log (base 2) 8? The answer should be 3....that is it is the inverse calculation of 2 cubed =8. Can any one help with the log calculation? Yes look you can't enter the base in calculators it's default ...

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Question about FX570MS Scientific Calculator

1 Answer

...log base 2 To calculate the log base 2 of a value, calculate its log and then divide by the log of 2. You can use either the log or the ln keys, but be consistent. For example, to calculate the log ...

Question about TI-84 Plus Calculator

1 Answer

...log(2) from log(4) I get .301029957, the answer should be 2, what is wrong? The answer for the problem log(4) - log(2) is actually 0.301, so the good news is that your calculator is working properly! ...

Question about FX350MS Scientific Calculator

1 Answer

...log base 2 You can't. However, you can calculate the log base 2 of any number by calculating log2(x) = log(x)/log(2) = ln(x)/ln(2) That is, the log base 2 of any number is the log of that number ...

Question about TI-30 Xa Solar Calculator

1 Answer

log(x) / log(b) = ln(x) / ln(b) You can use either the common log (log) or the natural log (ln), as long as you're consistent. So, to calculate log2(2.5), press 2 . 5 log / 2 log = or 2 . 5 ln / 2 ln

Question about FX-300MS Calculator

1 Answer

How can i perform Log 9 base 2 log(9)/log(2) (both base 10) is equal to log(9)base 2. This works for anything, try it backwards and you'll find that 2^(log(9)/log(2)) is equal to 9.

...Log Version = 2,12,32,426 [HVD] OS Info 6 0 S 2 0 [VC] ====== Start time: 1/5/2012, 2:12:7 [VC] Module VC Log Version = 1,7,15,426 [VC] OS Info 6 0 S 2 0 [VC] ====== Start time: 1/5/2012, 2:12:7 [VC] ...

Question about FX-300MS Calculator

1 Answer

...log(x^2) + log(3/4) = log(2x + 3/4) log(3/4*x^2) = log(2x + 3/4) 3/4*x^2 = 2x + 3/4 multiply equation by 4: 3x^2 = 8x + 3 3x^2 - 8x - 3 = 0 solve this quadratic eq. and you get x1 = 3 x2 = -1/3 does ...

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